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How many kg of 0.862% of chalcopyrite ore (CuFeS2) will be necessary to produce 1.00kg of pure copper?
How many kg of 0.862% of chalcopyrite ore (CuFeS2) will be necessary to produce 1.00kg of pure copper?
balanced equation is as follows: (NOTE: this is a chemical reaction that occurs in a sequence, hence the 2 equations)
4CuFeS2 + 7O2 ==>4CuS + 2Fe2O3 + 4 SO2
4CuS + 4O2 ==> 4Cu + 4SO2
Its all very good in theory however real life its much more complicated than that. Firstly the ore needs to be processed through a mill and flotation circuit. The end result will depend on how the metallurgist has set the mill. .862% Cu mill feed is marginal and will produce a weak concentrate (cons) grade when compared to a higher grade mill feed. It the final cons grade that will indicate how much Cu is available for recovery.
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